Notes
four squares vi solution

Solution to the Four Squares VI Puzzle

Solution by Pythagoras' Theorem

As in the above diagram, let $a$, $b$, and $c$ be the side lengths of the squares, and $d$ is the difference between the top of the large yellow square and the lower white square. Applying Pythagoras' Theorem to the triangle shows that:

From the diagram, $2c = a + b$ and $d = a - c$, so $2d = a - b$. Therefore:

Therefore